The straight line l has the equation 3y=4x+7
the point a has coordinates (3,-5)
find an equation of a straight line that is perpendicular to l and passes through a

Respuesta :

We can rewrite the equation of line l in slope-intercept form as y = ¾ x + 7/3, which means the slope of line l is 3/4.

Since perpendicular lines have slopes that are negative reciprocals of each other, the slope of the line we need to find is -4/3.

Substituting into point-slope form,

y + 5 = -4/3 (x - 3)

y + 5 = -4/3 x + 4

y = -4/3 x - 1

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