Answer: 147 mL
Explanation:
Given:
Molarity of the sodium bromide (NaBr) solution (M1) = 1.75 M
Volume of the solution (V1) = 84 mL
Molarity of the diluted NaBr solution (M2) = 1 M
Using the dilution formula to solve for V2:
[tex]\begin{gathered}M_{1} V_{1}=M_{2} V_{2} \\V_{2}=(1.75 \mathrm{M} \times 84 \mathrm{~mL}) / 1 \mathrm{M} \\V_{2}=147 \mathrm{~mL}\end{gathered}[/tex]
Therefore, the new volume of the solution is 147 mL
