A geyser shoots water straight up into the air with a velocity of 28.0 m/s. how
high does the water go before it starts coming back down? (hint: peinitial = 0,
kefinal=0)
a. 1.43 m
b. 40.0 m
c. 80.0 m
d. 23.4 m

Respuesta :

The maximum height reached by the water  before it starts coming back down is 40 m.

Maximum height reached by the water

The maximum height reached by the water  before it starts coming back down is calculated by applying the principle of conservation of energy.

P.E = K.E

mgh = ¹/₂mv²

gh = ¹/₂v²

h = (v²)/(2g)

h = (28²)/(2 x 9.8)

h = 40 m

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