The current flowing through a light bulb which is in parallel with the
hairdryer is 10 A.
The current is the stream of charges which flow inside the conductors when connected across the end of voltage.
In a parallel circuit, a 50 ohm hairdryer has 2.4 amps of current flowing through it.
So, I = 2.4 A and R = 50 ohm
From the Ohm's law,
V =IR
By substituting the values, we get
V = 2.4 x 50
V =120 Volts
Let the power of the lamp is 12 Watt.
The power related to the voltage and current as
P = VI
12 = 120 x I
I = 10 A
Thus, the current flowing through a light bulb is 10 A.
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