The solution to the quadratic equation is given as follows: [tex]q = -\frac{1}{3}[/tex]
What is a quadratic function?
A quadratic function is given according to the following rule:
[tex]y = ax^2 + bx + c[/tex]
The solutions are:
- [tex]x_1 = \frac{-b + \sqrt{\Delta}}{2a}[/tex]
- [tex]x_2 = \frac{-b - \sqrt{\Delta}}{2a}[/tex]
In which:
[tex]\Delta = b^2 - 4ac[/tex]
In this problem, the equation is:
9q² + 6q + 1.
The coefficients are a = 9,b = 6, c = 1, hence:
[tex]\Delta = 6^2 - 4(9)(1) = 0[/tex]
[tex]q_1 = \frac{-6 + \sqrt{0}}{2(9)} = -\frac{1}{3}[/tex]
[tex]q_2 = \frac{-6 - \sqrt{0}}{2(9)} = -\frac{1}{3}[/tex]
More can be learned about quadratic functions at https://brainly.com/question/24737967
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