[tex]\rm sin\theta = \frac{10}{x} \ , cos \theta = \frac{\sqrt{10^2-x^2}}{x} ,\ \rm tan \theta =\frac{10}{\sqrt{10^2-x^2}}[/tex] are the obtained values.
What is trigonometry?
Trigonometry deals with the relationship between the sides and angles of a right-angle triangle.
From ΔABC it is obtained that;
From the pythogorous theorem;
h²=p²+b²
x²=10²+b²
b=√(10²-x²)
h=x
p=10
[tex]\rm sin \theta =\frac{p}{h} \\\\ sin\theta = \frac{10}{x}[/tex]
[tex]\rm cos \theta =\frac{b}{h} \\\\ cos \theta = \frac{\sqrt{10^2-x^2}}{x}[/tex]
[tex]\rm tan \theta = \frac{p}{b} \\\\ tan \theta =\frac{10}{\sqrt{10^2-x^2}}[/tex]
Hence for the given triangle, the sinΘ,cosΘ, and tanΘ value is obtained above.
To learn more about trigonometry, refer to the link https://brainly.com/question/26719838
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