Respuesta :
9.5314 L is the volume of nitrogen dioxide formed at 103.25 kPa and 22.75 °C.
What is an ideal gas equation?
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
Given data:
Oxygen produced - 1.618 gram
Decomposition of [tex]N_2O_5[/tex] takes place.
Find - Amount of [tex]NO_2[/tex] produced.
The decomposition reaction is as follows -
[tex]2N_2O_5[/tex]--> [tex]4NO_2 + O_2[/tex]
Moles of [tex]O_2[/tex] gas =[tex]\frac{1.6}{16}[/tex] =0.1 moles.
1 mole of [tex]O_2[/tex] is produced from 2 moles of dinitrogen pentoxide
0.1 mole of [tex]O_2[/tex] will be produced from = 0.2 moles.
Now, 2 moles of dinitrogen pentoxide produce 4 moles of [tex]NO_2[/tex]
[tex]NO_2[/tex] produced will be - 0.4 moles.
Weight of [tex]NO_2[/tex] produced - 0.4 X 46
Weight of [tex]NO_2[/tex] produced - 18.4 gram
Thus, grams of [tex]NO_2[/tex] produced are 18.4
Now calculate the volume of [tex]NO_2[/tex]
Given data are:
P=103.25 kPa =1.01899827 atm
T= 22.75 °C +273 = 295.75 K
n=0.4 moles
V=?
R= 0.0821 liter·atm/mol·K
Putting the value in PV=nRT
V = [tex]\frac{nRT}{P}[/tex]
V = [tex]\frac{0.4 \;moles \;X \;0.0821\; liter\;atm/\;mol \;K X \;295.75 \;K}{1.01899827 atm}[/tex]
V= 9.5314 L
Hence, 9.5314 L is the volume of nitrogen dioxide formed at 103.25 kPa and 22.75 °C.
Learn more about the ideal gas equation here:
https://brainly.com/question/13450124
#SPJ1
