contestada

uring 2008, college work-study students earn a mean of $1478. Assume that a sample consisting 45 of the work-study students at a large university was found to have earned a mean of $1503 during that year with a standard deviation $210. At 5% significance level does the average earning of work-study students were significantly higher than the national mean?

Respuesta :

Parrain

Based on the national mean and the average earning of the work-study students, at a 5% significance level, the average earning of the work-study students IS NOT higher than the national mean.

Is the average earning greater than the national mean at 5% significance?

Degrees of freedom:

= n - 1

= 45 -1

= 44

Significance level = 5%.

First find the t-value:

= (Sample mean - Population mean) ÷ standard deviation of sample / √samle mean

= (1,503 - 1,478) ÷ (210 / √45)

= 0.80

We then use the t-table to find the t- value with the degrees of freedom of 44 and a significance level 5%. That t-value is 1.680.

With the calculated t-value of 0.80 being less than the t-value from the table of 1.680, we cannot conclude that the average earning of work-study students is significantly higher than the national mean.

Find out more on the significance level at https://brainly.com/question/15848236.

#SPJ1

Otras preguntas