To solve this problem, we need to factor both
⇒ numerator: [tex]x^2-4x+4[/tex]
⇒ denominator: [tex]x^2-4[/tex]
Let's factor:
⇒ [tex]x^2-4x+4=(x-2)(x-2)\\[/tex]
⇒ [tex]x^2-4=(x+2)(x-2)[/tex]
Let's put it back into the fraction:
[tex]\frac{x^2-4x+4}{x^2-4}=\frac{(x-2)(x-2)}{(x+2)(x-2)} =\frac{x-2}{x+2}*\frac{x-2}{x-2} =\frac{x-2}{x+2} *1=\frac{x-2}{x+2}[/tex]
Answer: Choice (3) or [tex]\frac{x-2}{x+2}[/tex]
