Respuesta :

Answer:

  • No real roots

Step-by-step explanation:

Given equation:

  • x² + 2x + 3 = 0

On comparing the equation by ax² + bx + x = 0, We get: a = 1, b = 2 and c = 3

To Find the nature of the roots of the equation firstly we need to find the discriminant of the equation. The expression b²- 4ac is called the discriminant.

[tex]~[/tex]

  • Two Distinct real roots, if b² - 4ac > 0
  • Two equal real roots, if b² - 4ac = 0
  • No real roots, if b² - 4ac < 0

[tex] \\ \: \: \dashrightarrow \: \: \: \sf {b}^{2} - 4ac = 0 \\ \\ \\\: \: \dashrightarrow \: \: \: \sf (2)² - 4 \times 1 \times 3 = 0 \\ \\ \\ \: \: \dashrightarrow \: \: \: \sf 4 - 4 \times 1 \times 3 = 0 \\ \\ \\ \: \: \dashrightarrow \: \: \: \sf 4 - 12 = 0 \\ \\ \\ \: \: \dashrightarrow \: \: \: \sf {\underline{\boxed{\sf{\purple{ -8 > 0}}}}} \\ \\ [/tex]

The discriminant is smaller than 0.

  • Hence, Equation has no real roots (no solution)

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