Let's set some variables before we solve:
- First number ⇒ x
- Second number ⇒ y
Okay's lets read the question
- 'x' is 5 more than three times 'y'
⇒ [tex]x = 3y +5[/tex]
⇒ [tex]x-3y=5[/tex]
⇒ [tex]x - y = 35[/tex]
Let's put the two equations together and solve
[tex]x-3y=5 --equation1\\[/tex]
[tex]x-y=35 -- equation2[/tex]
(equation2) - (equation1)
[tex]2y = 30\\y = 15 -- equation 3[/tex]
(equation 3)'s value of y into (equation2)
[tex]x - 15= 35\\x = 50[/tex]
Thus: [tex]x = 50[/tex] and [tex]y = 15[/tex]
The larger number is 50
Answer: 50 or Choice 3
Hope that helps!
