Line passes through (2, -1) and slope of 1/3
Step 1
y = mx + b, Identify: x = 2, y = -1, slope: [tex]\sf \frac{1}{3}[/tex]
insert following values
[tex]\rightarrow \sf -1 = \dfrac{1}{3} (2) + b[/tex]
multiply
[tex]\rightarrow \sf -1 = \dfrac{2}{3} + b[/tex]
switch sides
[tex]\rightarrow \sf b = -1 - \dfrac{2}{3}[/tex]
subtract
[tex]\sf \rightarrow b = -\dfrac{5}{3}[/tex]
convert to mixed fraction
[tex]\sf \rightarrow b = -1\dfrac{2}{3}[/tex]
Step 2
y = mx + b, m = [tex]\sf \frac{1}{3}[/tex], b = [tex]-1\frac{2}{3}[/tex]
insert following values
[tex]\rightarrow \sf y = \dfrac{1}{3} x -1\dfrac{2}{3}[/tex]
