Please help with 6 and 7

Answer:
6. The number is [tex]-5[/tex]
7. The two numbers are [tex]10[/tex] and [tex]11[/tex]
Step-by-step explanation:
Question six can be re-worded to create the following expression:
[tex]-2=\frac{4x+10}{5}[/tex]
Solve for x to find the number:
[tex]-2=\frac{4x+10}{5}\\-10=4x+10\\-20=4x\\\frac{-20}{4} = x\\-5 = x[/tex]
Question seven can be solved by first listing the constraints (assuming x is smaller than y):
To get the numbers, we can create a system of linear equations. First, solve for [tex]y[/tex] in each expression:
[tex]y = x+1[/tex]
[tex]2y = 3x-8\\y = \frac{3}{2}x - 4[/tex]
Solve for [tex]x[/tex]:
[tex]x+ 1 = \frac{3}{2}x - 4\\x + 5 = \frac{3}{2}x\\5 = \frac{3}{2}x - x\\5 = \frac{1}{2}x\\10 = x[/tex]
Solve for [tex]y[/tex]:
[tex]y = x + 1\\y = 10 + 1\\y= 11[/tex]
Answer:
see explanation
Step-by-step explanation:
(6)
let n be the number then the sum of 4 times the number and 10 is 4n + 10
so
[tex]\frac{4n+10}{5}[/tex] = - 2 ( multiply both sides by 5 to clear the fraction )
4n + 10 = - 10 ( subtract 10 from both sides )
4n = - 20 ( divide both sides by 4 )
n = - 5
(7)
let the consecutive integers be n and n + 1 , then
3n = 2(n + 1) - 8 ← distribute parenthesis and simplify right side
3n = 2n + 2 - 8
3n = 2n - 6 ( subtract 2n from both sides )
n = - 6 and n + 1 = - 6 + 1 = - 5
the 2 integers are - 6 and - 5