find the surface area of the pyramid. the surface area of the pyramid is __in squared.

Answer:
[tex]561.08in^{2}[/tex]
Step-by-step explanation:
[tex]S A = lw + l[/tex] [tex]\sqrt{(\frac{w}{2})^{2} + h^{2} } + w[/tex] [tex]\sqrt{(\frac{l}{2})^{2} + h^{2} }[/tex]
[tex]SA = 14(14) + 14 \sqrt{(\frac{14}{2})^{2} + 11^{2} }+ 14 \sqrt{(\frac{14}{2})^{2} + 11^{2} } = 561.08in^{2}[/tex]