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A 1.1-m tall child is standing 6.0 m from a spherical convex mirror. The child’s image is 0.40 m behind the mirror. What is the image height and focal length of the mirror?

Respuesta :

Answer:

1 / i + 1 / o = 1 / f        thin lens equation

(i + o) / o i = 1 / f

f = o i / (i + o) = 6 * -.4 / (-.4 + 6) = -2.4 / 5.6 = -.42 m

The focal length is -.42 m indicating a convex mirror

M = -I / O    =   -.4 / 6 = -.067    negative magnification indicates erect image

O = M * 1.1 = -.067 * 1.1 = -.073 m     height of image

One must be careful with signs because they can vary with textbooks

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