hishawi hishawi

04-05-2022
Mathematics

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Write the standard form of the equation of a circle with radius 3 and center (11, 3)

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Аноним Аноним

04-05-2022

Answer:

x² - 22x + y² - 6y + 121 = 0

Step-by-step explanation:

General Form of Equation

(x - h)² + (y - k)² = r²

Solving

(x - 11)² + (y - 3)² = (3)²
x² - 22x + 121 + y² - 6y + 9 = 9
x² - 22x + y² - 6y + 121 = 0

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jbooth12 jbooth12

04-05-2022

Answer:

(x+11)2+(y−3)2=81

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Step-by-step explanation:

Answer Link

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