When 6.1 moles of Cu is reacted with excess S 3.05 number of mole of Cu2S are produced.
The balance equation of the above reaction is:
2Cu +S --> Cu2S
This means that 2 moles of Cu = 1 mole of Cu2S
Therefore 6.1 moles of Cu = X mole of Cu2S
Make X the subject of formula,
X = 6.1 ×1/2
X = 3.05 moles
Therefore, when 6.1 moles of Cu is reacted with excess S 3.05 number of mole of Cu2S are produced.
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