Answer:
34.86 unit²
Step-by-step explanation:
[tex]A_{triangle}[/tex] = [tex]\sqrt{s(s-a)(s-b)(s-c)}[/tex] , where s = [tex]\frac{P}{2}[/tex] ; P = a + b + c
[tex]A_{hexagon}[/tex] = 6 × [tex]A_{triangle}[/tex]
[tex]A_{circle}[/tex] = [tex]\pi r^2[/tex]
[tex]\pi[/tex] ≈ [tex]\frac{22}{7}[/tex]
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