The zeros or roots of the quadratic function f(x) = 6x² – 24x +1 were found with the help of the formula.
The given quadratic equation is:
[tex]6x^{2} -24x+1=0[/tex]
Any equation of the form [tex]ax^{2} +bx+c=0[/tex] where a≠0 is called a quadratic equation.
We know the solution of a quadratic equation [tex]ax^{2} +bx+c=0[/tex] is given by:
[tex]x=\frac{-b +\sqrt{b^{2}-4ac } }{2a}[/tex]
[tex]x=\frac{-b -\sqrt{b^{2}-4ac } }{2a}[/tex]
So, the solution of the quadratic equation [tex]6x^{2} -24x+1=0[/tex] will be:
[tex]x=\frac{-(-24) +\sqrt{(-24)^{2}-4(6)(1) } }{2*6}[/tex]
[tex]x=\frac{12+\sqrt{138} }{6}[/tex]
[tex]x=\frac{12-\sqrt{138} }{6}[/tex]
Thus, the zeros or roots of the quadratic function f(x) = 6x² – 24x +1 were found with the help of the formula.
To get more about quadratic equations visit:
https://brainly.com/question/1214333
Answer:
its the fourth one on edge D
Step-by-step explanation:
x=2+23/6 or x=2-23/6
