Respuesta :

DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's find the specific heat of sample using given formula :

[tex]\qquad \tt \dashrightarrow \:Q = m \: s \triangle T[/tex]

where,

  • Q = heat transfer

  • m = mass

  • S = specific heat

  • [tex] \tt \triangle T [/tex] = change in temperature

[tex]\qquad \tt \dashrightarrow \:50.9 = 12 \times \: s \times 6[/tex]

[tex]\qquad \tt \dashrightarrow \:s = \dfrac{50.9}{72} [/tex]

[tex]\qquad \tt \dashrightarrow \:s = 0.707 \: [/tex]

Therefore, specific heat of that substance is 0.707 J/g°C

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