Answer:
Step-by-step explanation:
Given the slope-intercept form:[tex]y=\frac{1}{3}x-2[/tex]
Slope-intercept form: [tex]y=mx+b[/tex]
We substitute our x-values (-9, -3, 0, 6, and 9) for x in [tex]y=\frac{1}{3}x-2[/tex] to find the y-values.
For -9:
[tex]y=\frac{1}{3}x-2 < ==substitute\ -9\ for\ x\\\\y=\frac{1}{3}(-9)-2\\\\y=\frac{-9}{3}-2 < ==divide\ (don't\ forget\ the\ signs)\\\\y=-3-2 < ==add\ or\ subtract\\\\y=-5 < =value\ of\ y\\\\(-9,-5)[/tex]
For -3:
[tex]y=\frac{1}{3}x-2 < ==substitute\ -3\ for\ x\\\\y=\frac{1}{3}(-3)-2\\\\y=\frac{-3}{3}-2 < ==divide\ (don't\ forget\ the\ signs)\\\\y=-1-2 < ==add\ or\ subtract\\\\y=-3 < =value\ of\ y\\\\(-3,-3)[/tex]
For 0:
[tex]y=\frac{1}{3}x-2 < ==substitute\ 0\ for\ x\\\\y=\frac{1}{3}(0)-2 < ==any\ number\ multiplied\ by\ 0\ equals\ zero\\\\y=\frac{0}{3}-2 < ==divide\ (don't\ forget\ the\ signs)-zero\ divided\ by\ any\ \#\ equals\ 0\\\\y=0-2 < ==add\ or\ subtract\\\\y=-2 < =value\ of\ y\\\\(0,-2)[/tex]
For 6:
[tex]y=\frac{1}{3}x-2 < ==substitute\ 6\ for\ x\\\\y=\frac{1}{3}(6)-2\\\\y=\frac{6}{3}-2 < ==divide\ (don't\ forget\ the\ signs)\\\\y=2-2 < ==add\ or\ subtract\\\\y=0 < =value\ of\ y\\\\(6,0)[/tex]
For 9:
[tex]y=\frac{1}{3}x-2 < ==substitute\ 9\ for\ x\\\\y=\frac{1}{3}(9)-2\\\\y=\frac{9}{3}-2 < ==divide\ (don't\ forget\ the\ signs)\\\\y=3-2 < ==add\ or\ subtract\\\\y=1 < =value\ of\ y\\\\(9,1)[/tex]
*View the attached graph to verify these answers*
Hope this helps!
