Which is the equation of a circle whose center is at the origin and that passes through the point (3, 5)?

Answer:
x² + y² = 34
Formula:
Here find the radius using distance formula: → origin : (0, 0)
Thus the equation of circle:
Answer:
H. [tex]x^2+y^2=34[/tex]
Step-by-step explanation:
Equation of a circle (in standard form)
[tex](x-h)^2+(y-k)^2=r^2[/tex]
(where (h, k) is the center and r is the radius of the circle)
Given center = (0, 0):
[tex]\implies (x-0)^2+(y-0)^2=r^2[/tex]
[tex]\implies x^2+y^2=r^2[/tex]
As the circle passes through point (3, 5):
[tex]\implies 3^2+5^2=r^2[/tex]
[tex]\implies r^2=34[/tex]
Final equation
[tex]x^2+y^2=34[/tex]