Assuming ℎ1 = 11 feet and ℎ 2 = 3 feet, the storage of the facility is going to be 603 cubic feet, which is more than 576 cubic feet
The diameter of the building has been given as 8cm
radius = d/2 = 8/2 = 4
Maximum height = h1 + h2 = 14
Find the volume of the fertilizer that is containeed in both of the trucks
2(12x4x6) = 576 feet
From the height of 14 feets we have to assume
h1 = 11 ft,
h2 = 3 ft
[tex]volume =\frac{1}{3} \pi r^{2} h2 + \pi r^{2} h1[/tex]
= 0.333*3.14*4²*3 + 3.14*4²*11
= 602.8 ft ≈ 603
Read more on volume here: https://brainly.com/question/12410983
