For an art project, a cone is covered with paper without any gaps or overlaps. The height of the cone is 28 inches and its diameter is 14 inches.


What is the surface area of the covering to the nearest square inch?

Respuesta :

The surface area of the covering of the cone to the nearest square inches is 788 inches²

Surface area of a cone

surface area of a cone = πr(r + l)

where

  • r = radius
  • l = slant length

Therefore,

diameter = 2(radius)

14 = 2r

r = 14 / 2

r = 7 inches

l² = 7² + 28²

l = √49 + 784

l = √833

l = 28.8617393793

l = 28.86 inches

Therefore,

surface area = 3.14 × 7 (7 + 28.86)

surface area = 21.98 × 35.86

surface area = 788.2028

surface area = 788 inches²

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