contestada

Two like-charged particles are placed close to each other. How would the force of repulsion be affected if the charge on one of the particles is doubled and that on the other is reduced to half the original value? A) The force would remain the same. B) The force would become half the original value. C) The force would become twice the original value. D) The force would become four times the original value.

Respuesta :

shubhamchouhanvrVT

The force of repulsion between two charged particles will remain the same

What will be the effect on the force of two charged particles?

We know that from Columb's law force between two charged particles will be given by

[tex]F=k \dfrac{q_1q_2}{r^2}[/tex]

Now from the condition

if the charge on one of the particles is doubled and that on the other is reduced to half the original value

[tex]q_1'=2q_1[/tex]

and

[tex]q_2'=\dfrac{q_2}{2}[/tex]

Use the above values in the formula

[tex]F'=k\dfrac{q_1'q_2'}{r^2}[/tex]

[tex]F'=k\dfrac{2q_1 \dfrac{q_2}{2} }{r^2}[/tex]

[tex]F'=k\dfrac{q_1q_2}{r^2}[/tex]

So [tex]F=F'[/tex]

Thus the force of repulsion between two charged particles will remain the same

To know more about Columb's law follow

https://brainly.com/question/506926

Otras preguntas