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Calculate the mass of an electron traveling at 2.95×10^8 ms if its wavelength is 1.30×10^−12 m. Use 6.626×10^−34kg m2s for Planck's constant.

Your answer should include three significant figures.

Respuesta :

temdan2001

With the use of De Broglie equation, the mass of the electron is 1.73 x [tex]10^{-30}[/tex] kg

De Broglie Equation

De Broglie deals with wave - particle duality of some matter. He believe that particle can also exhibit wave properties.

According to De Broglie equation,

λ = h/p

Where

  • λ = wavelength
  • h = Planck's constant
  • p = momentum

Given that an electron of wavelength 1.30×10^−12 m is traveling at 2.95×10^8 m/s . Use 6.626×10^−34kg m2s for Planck's constant.

The parameters are

  • λ = wavelength = 1.3 x [tex]10^{-12}[/tex] m
  • h = Planck's constant = 6.626 x [tex]10^{-34}[/tex]
  • v = velocity = 2.95 x [tex]10^{8}[/tex] m/s
  • m = mass = ?

To calculate the mass of the electron, we will make use of de Broglie equation.

λ = h / mv

Make mass m the subject of the formula

mvλ = h

m = h/λv

Substitute all the parameters

m = 6.626 x [tex]10^{-34}[/tex] / (1.3 x [tex]10^{-12}[/tex])(2.95 x [tex]10^{8}[/tex])

m = 1.73 x [tex]10^{-30}[/tex] kg

Therefore, the mass of the electron is 1.73 x [tex]10^{-30}[/tex] kg

Learn more about De Broglie Equation here: https://brainly.com/question/20724696

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