contestada

A block of mass 0. 5kg on a horizontal surface is attached to a horizontal spring of negligible mass and spring constant 50n/m. The other end of the spring is attached to a wall, and there is negligible friction between the block and the horizontal surface. When the spring is unstretched, the block is located at x=0m. The block is then pulled to x=0. 3m and released from rest so that the block-spring system oscillates between x=−0. 3m and x=0. 3m. What is the magnitude of the acceleration of the block and the direction of the net force exerted on the block when it is located at x=0. 3m?

Respuesta :

oladayoademosu

a. The magnitude of the acceleration is 30 m/s²

b. The net force on the block is 15 N and directed towards the negative x axis.

a. The acceleration of the block

The magnitude of the acceleration is 30 m/s²

The acceleration of the block is given by a = -ω²x where

  • ω = angular speed of block = k/m where
  • k = spring constant = 50 N/m and
  • m = mass of block = 0.5 kg and
  • x = position of block = 0.3 m

So, a = -ω²x

a = -kx/m

Substituting the values of the variables into the equation, we have

a = - 50 N/m × 0.3 m/0.5 kg

a = -15 N/0.5 kg

a = -30 N/kg

a = -30 m/s²

So, the magnitude of the acceleration is 30 m/s²

b. The net force on the block

The net force on the block is 15 N and directed towards the negative x axis.

The net force on the block is given by F = ma where

  • m = mass of block = 0.5 kg and
  • a = acceleration of block = -30 m/s²

So, F = ma

F = 0.5 kg × -30 m/s²

F = -15 kgm/s²

F = -15 N

We see that the force is negative.

So, the net force on the block is 15 N and directed towards the negative x axis.

Learn more about spring force here:

https://brainly.com/question/26825211

Otras preguntas