Answer:
x's term to term rule = add 2
x's position to term rule= (n-1)×2
y's term to term rule = subtract 1
y's position to term rule= 2+(n-1)×(-1)
Step-by-step explanation:
0 = 1st term of x
0+2 =2 =sec term of
2+2=4 =third term of x
that's why x's termto term rule is add 2.
(n-1)2
1st term of x = (1-1)2=0
2nd term of x= (2-1)2=1×2=2
3rd term of x=(3-1)2=2×2=4
2= y's first term
2-1=1 =sec term of y
1-1=0 =third term of y
0-1= -1= fourth term of y
that's why y's term to term rule is subtract 1.
2+(n-1)×(-1)
first term of y:
2+(1-1)×(-1)
=2+0=2
2nd term of y:
2+(2-1)(-1)
2+(-1)=1
Third term of y= 2+(3-1)(-1)
=2+[2×(-1)]
=2+(-2)
=0
