Using the formula for the area and circumference of a circle, we have the following answers:
1. radius = 2 in. (given)
Diameter = 4 in.
Circumference = 12.56 in.
Area = 12.56 in.²
2. radius = 10 in.
Diameter = 20 in. (given)
Circumference = 62.8 in.
Area = 314 in.²
3. radius = 5 in.
Diameter = 10 in. (given)
Circumference = 31.4 in.
Area = 78.5 in.²
4. radius = 20 in.
Diameter = 40 in. (given)
Circumference = 125.6 in.
Area = 1,256 in.²
5. radius = 18 in. (given)
Diameter = 36 in.
Circumference = 113.04 in.
Area = 1,017.36 in.²
6. radius = 8 in. (given)
Diameter = 16 in.
Circumference = 50.24 in.
Area = 200.96 in.²
7. radius = 12 in. (given)
Diameter = 24 in.
Circumference = 75.36 in.
Area = 452.16 in.²
8. radius = 16 in.
Diameter = 32 in. (given)
Circumference = 100.48 in.
Area = 803.84 in.²
9. radius = 15 in. (given)
Diameter = 30 in.
Circumference = 94.2 in.
Area = 706.5 in.²
What is the Area and Circumference of a Circle?
- Area of a circle = πr²
- Circumference of a circle = 2πr or πd, where r is radius and d is diameter.
1. radius = 2 in. (given)
Diameter = 2(2) = 4 in.
Circumference = πd = π(4) = 12.56 in.
Area = πr² = π(2²) = 12.56 in.²
2. radius = 1/2(20) = 10 in.
Diameter = 20 in. (given)
Circumference = πd = π(20) = 62.8 in.
Area = πr² = π(10²) = 314 in.²
3. radius = 1/2(10) = 5 in.
Diameter = 10 in. (given)
Circumference = πd = π(10) = 31.4 in.
Area = πr² = π(5²) = 78.5 in.²
4. radius = 1/2(40) = 20 in.
Diameter = 40 in. (given)
Circumference = πd = π(40) = 125.6 in.
Area = πr² = π(20²) = 1,256 in.²
5. radius = 18 in. (given)
Diameter = 2(18) = 36 in.
Circumference = πd = π(36) = 113.04 in.
Area = πr² = π(18²) = 1,017.36 in.²
6. radius = 8 in. (given)
Diameter = 2(8) = 16 in.
Circumference = πd = π(16) = 50.24 in.
Area = πr² = π(8²) = 200.96 in.²
7. radius = 12 in. (given)
Diameter = 2(12) = 24 in.
Circumference = πd = π(24) = 75.36 in.
Area = πr² = π(12²) = 452.16 in.²
8. radius = 1/2(32) = 16 in.
Diameter = 32 in. (given)
Circumference = πd = π(32) = 100.48 in.
Area = πr² = π(16²) = 803.84 in.²
9. radius = 15 in. (given)
Diameter = 2(15) = 30 in.
Circumference = πd = π(30) = 94.2 in.
Area = πr² = π(15²) = 706.5 in.²
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