A) The experimental probabilities are:
R = 0.45, B = 0.4, and Y = 0.15
From this, we can expect to get a red ball on the next draw.
B) This can happen because the experimental probabilities are bad estimations, or because the balls on the machine are not replaced.
A) The probability of getting each color will be given by the quotient of the number of balls of that color and the total number of balls.
For example, we know that 100 people buy gumballs, and 45 of them got red ones, so the experimental probability of getting a red gumball is:
R = 45/100 = 0.45
40 got a blue ball, so the probability of getting a blue ball is:
B = 40/100 = 0.4
15 got a yellow gumball, so the probability here is:
Y = 15/100 = 0.15
As you can see, the experimental probability of getting a red gumball is 3 times the probability of getting a yellow one. based on that, we can expect that the next gumball out from that machine will be red.
B) So now 10 more people go to the machine, and they get:
7 yellow, 1 red, and 2 blue gumballs.
This clearly does not follow the experimental probability we got above, why this may happen?
There are two main reasons.
First, to get a valuable experimental probability an experiment must be performed a lot of times, 100 is a ratter a small number. So the experimental probability that we got on point A may be a really bad estimation.
On another hand, there is a possibility that the gumballs in the machine are not being replaced. So initially, there is a fixed number of red, yellow, and blue balls.
This would mean that if we remove one red ball on the first try. Then for the next try, the probability of getting a red ball will be smaller (because now the machine has fewer red balls).
Then, because out of the 100 first balls most were red or blue, we can assume that most of the remaining balls on the machine are now yellow, and then the probability of getting a yellow ball is increased.
If you want to learn more about probability, you can read:
https://brainly.com/question/251701
