Taking into account the reaction stoichiometry, 5 moles of CO₂ can be formed from 1.25 mol butane and excess oxygen.
In first place, the balanced reaction is:
2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
The following rule of three can be applied: if by reaction stoichiometry 2 moles of C₄H₁₀ form 8 moles of CO₂, 1.25 moles of C₄H₁₀ form how many moles of CO₂?
[tex]moles of CO_{2} =\frac{1.25 moles of C_{4} H_{10}x8 moles of CO_{2}}{2 moles of C_{4} H_{10}}[/tex]
moles of CO₂= 5 moles
Then, 5 moles of CO₂ can be formed from 1.25 mol butane and excess oxygen.
Learn more about the reaction stoichiometry:
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