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The following questions pertain to a 0.50 M solution of HOCl at 25℃. pKa = 7.46 at 25℃. a. Find the concentration of all species present in the solution at equilibrium. b. Find the pH of the solution. c. Identify the strongest base in this system.

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The concentration of all species, the pH of the solution, and the strongest base is respectively given as)

a

  • C_HOCl=0.5
  • C_H3O=1.137*10^{-7}
  • ClO=1.137*10^{-4}

b)pH=3.88

c)ClO-

What are the concentration of all species, the pH of the solution, and the strongest base?

Question Parameters:

a 0.50 M solution of HOCl at 25℃. pKa = 7.46 at 25â„

Generally, the equation for the Chemical Reaction  is mathematically given as

HOCl=H30+ClO

Therefore

ka=\frac{H3O(ClO)}{HOCl}

Ka=10^{-7.46}

x.x/0.5-x=10^{-7.46}

x=1.317*10^{-4}

In conclusion

a)

the concentration HOCl

C_HOCl=0.5-1.137*10^{-4}

C_HOCl=0.5

the concentration H3O

C_H3O=1.137*10^{-7}

the concentration ClO

ClO=1.137*10^{-4}

b)

pH=-log(1.317*10^{-4})

pH=3.88

c)

The strongest base of the three is the

ClO-

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