[tex]\underline{\underline{\large\bf{Solution:-}}}\\[/tex]
[tex]\longrightarrow[/tex]Given is a quadratic equation which can be solved by splitting the middle term.
[tex]\leadsto[/tex]For this we have to look at factors of the constant term . Since here constant term term is- 6 so splitted middle term should have product equal to -6
[tex]\begin{gathered}\\\implies\quad \sf x^2-x-6=0 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf x^2-3x+2x-6=0 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf x(x-3)+2(x-3)=0 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf (x-3)(x+2) =0 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf (x-3) =0 \quad or \quad (x+2) =0\\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf x=3 \quad or \quad x= -2\\\\\end{gathered} [/tex]
[tex]\quad\therefore\: \sf x \:is \: \:3 \:or -2 [/tex]
