Answer:
Step-by-step explanation:
Let x be the total no. of strawberries, Let Sue be "S", Let Jim be "J" and Dan be "D"
S = 2x/7
J = 54+S -> J = 54+(2x/7)
D = 78
J+D = 5x/7
54+(2x/7)+78 = 5x/7
132+2x/7 = 5x/7
132 = (5x/7)-(2x/7)
132 = 3x/7
132*7 = 3x
924/3 = x
x = 308.
Therefore, there were initially 308 strawberries in the basket.
Of which; Sue had two-sevenths: 88, Jim had 142 and Dan had 78
To verify our answer, add these to see if we get 308
S+J+D = 308
88 + 142 + 78 = 308
