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Please answer!! (look at the picture)

Drag and drop the appropriate values for all of the trig functions using the right triangle below:
(you can use answers multiple times)

Please answer look at the picture Drag and drop the appropriate values for all of the trig functions using the right triangle below you can use answers multiple class=

Respuesta :

semsee45

Answer:

[tex]sinT=\dfrac{O}{H}=\dfrac{6\sqrt{2} }{19}[/tex]

[tex]cosT=\dfrac{A}{H}=\dfrac{17}{19}[/tex]

[tex]tanT=\dfrac{O}{A}=\dfrac{6\sqrt{2} }{17}[/tex]

[tex]sinS=\dfrac{O}{H}=\dfrac{17}{19}[/tex]

[tex]cosS=\dfrac{A}{H}=\dfrac{6\sqrt{2} }{19}[/tex]

[tex]tanS=\dfrac{O}{A}=\dfrac{17}{6\sqrt{2} }[/tex]

Step-by-step explanation:

Trig identities:

[tex]sin(x)=\dfrac{O}{H} \ \ \ \ \ cos(x)=\dfrac{A}{H} \ \ \ \ \ tan(x)=\dfrac{O}{A}[/tex]

where

  • x = angle
  • O = side opposite the angle
  • A = side adjacent the angle
  • H = hypotenuse

[tex]sinT=\dfrac{O}{H}=\dfrac{6\sqrt{2} }{19}[/tex]

[tex]cosT=\dfrac{A}{H}=\dfrac{17}{19}[/tex]

[tex]tanT=\dfrac{O}{A}=\dfrac{6\sqrt{2} }{17}[/tex]

[tex]sinS=\dfrac{O}{H}=\dfrac{17}{19}[/tex]

[tex]cosS=\dfrac{A}{H}=\dfrac{6\sqrt{2} }{19}[/tex]

[tex]tanS=\dfrac{O}{A}=\dfrac{17}{6\sqrt{2} }[/tex]