Respuesta :
Answer:
y = [tex]\frac{1}{4}[/tex] x + 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = - 4x - 4 ← is in slope- intercept form
with slope m = - 4
Given a line with slope m then the slope of a line perpendicular to it is
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-4}[/tex] = [tex]\frac{1}{4}[/tex] , then
y = [tex]\frac{1}{4}[/tex] x + c ← is the partial equation
to find c substitute (12, 5 ) into the partial equation
5 = 3 + c ⇒ c = 5 - 3 = 2
y = [tex]\frac{1}{4}[/tex] x + 2 ← equation of perpendicular line
Hi!
I can help you with joy!
An equation for a line looks like so: y=mx+b
m = slope and b = y-intercept
Guide to Finding Equations of Lines:
Recall that perpendicular lines have slopes that
[tex]\text{are opposite reciprocals}[/tex].
Clarification: We take the slope, flop it over, and change its sign:
[tex]\tt{y=-4x-4}\\Perpendicular:\\y=\frac{1}{4} (Slope)[/tex]
Equation:
(Point-Slope Form: y-y1=m(x-x1)
y-5=1/4(x-12)
y-5=1/4x-3
y=1/4x-3+5
y=1/4x+2 (Answer)
Hope it helps!
~Misty~
