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A 1.0 L volume of gas at 27.0°C exerts a pressure of 85.5 K PA what will the pressure be at 127°C assume constant volume

Respuesta :

Answer:

114 kPa

Explanation:

Using Gay-Lussac's law you get the equation [tex]\frac{P1}{T1} x \frac{P2}{T2}[/tex] and converting celcius you get the final equation of [tex]\frac{85.5}{27+273} x \frac{P2}{127+273}[/tex] . After dividing 85.5 by 27+273(300) you get 0.285 and then you multiply 0.285 by 127+273 (400). You finally get 114 kPa

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