The center of a circle is located at (2, 3) and has a radius of 6 units. Which equation represents this circle?
A- (x - 2)2 + (y - 3)2 = 6
B-(x - 2)2 + (y - 3)2 = 36
C- (x + 2)2 + (y + 3)2 = 36
D- (x + 2)2 + (y + 3)2 = 6

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facundo3141592 facundo3141592 · Answer 1 · 2022-02-28T12:42:05+01:00

By using the general equation for a circle, we will see that the correct option is:

(x - 2)^2 + (y - 3)^2 = 36

The general equation for a circle centered at the point (a, b) of radius R is given by:

(x - a)^2 + (y - b)^2 = R^2

In this case, the center is (2, 3) and the radius is R = 6 units, replacing that in the above equation we get:

(x - 2)^2 + (y - 3)^2 = 6^2

(x - 2)^2 + (y - 3)^2 = 36

So the correct option is B.

If you want to learn more about circles, you can read:

https://brainly.com/question/1559324

abidemiokin abidemiokin · Answer 2 · 2022-02-28T12:42:10+01:00

The equaton of the circle will be (x - 2)² + (y - 3)² = 6²

The standard equation of a circle is expressed as;

(x-a)² + (y-b)² = r²

where:

Given the following

r = 6units

(a, b) = (2,3)

Substitute

The equation of the circle will be (x - 2)² + (y - 3)² = 6²

Learn more on equastion of a circle here: https://brainly.com/question/1506955

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