anyone know this?? it’s finding the sine of a triangle!!

Answer:
I'm not sure what you want me to answer from this, so I solved for every variable:
Angle A: 83°
Side b: 6.29
Side c: 5.8
Step-by-step explanation:
-----Angle A:
Since the sum of the interior angles of a triangle ALWAYS equal 180°, we can solve for angle A as follows:
[tex]A+51+46=180\\A+97=180\\A=83[/tex]
-----Side b:
Here, we use the sin rule for finding sides, since we know all of the angles as well as one side:
[tex]\frac{a}{sin(A)} =\frac{b}{sin(B)} \\\frac{8}{sin(83)} =\frac{b}{sin(51)} \\8.06=\frac{b}{0.78} \\6.29=b[/tex]
-----Side c:
[tex]\frac{a}{sin(A)} =\frac{c}{sin(C)} \\\frac{8}{sin(83)}=\frac{c}{sin(46)} \\8.06=\frac{c}{0.72} \\5.8=c[/tex]