What is the solution to the equation below?
square root 2x/ square root x - 2 = 2

Answer:
[tex]x= 4[/tex]
Step-by-step explanation:
[tex]\frac{\sqrt{2x}}{\sqrt{x-2}\:}=2[/tex] [ bring √(x - 2) to the opposite side ]
[tex]\sqrt{2x} = 2\sqrt{x-2}[/tex]
[tex](\sqrt{2x} )^{2} = (2\sqrt{x-2})^2[/tex] [ square both sides ]
[tex]2x = 4(x-2)[/tex]
[tex]2x=4x-8[/tex]
[tex]2x - 4x = -8[/tex]
[tex]-2x = -8[/tex]
[tex]x= 4[/tex]
Answer:
x=4
Step-by-step explanation:
[tex]\dfrac{\sqrt{2x} }{\sqrt{x-2}}=2[/tex]
Multiply both sides by [tex]\sqrt{x-2}[/tex] :
[tex]\implies \sqrt{2x}=2\sqrt{x-2}[/tex]
Square both sides:
[tex]\implies 2x=4(x-2)\\\\\implies 2x=4x-8[/tex]
Add 8 to both sides:
[tex]\implies 2x+8=4x[/tex]
Subtract [tex]2x[/tex] from both sides:
[tex]\implies 8=2x[/tex]
Divide both sides by 4:
[tex]\implies x=4[/tex]