[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Here's the solution ~
Let's use Angle sum property of a triangle :
[tex]\qquad \sf \dashrightarrow \: 5x - 60\degree + 2x + 40\degree + 3x - 80 \degree= 180 \degree[/tex]
[tex]\qquad \sf \dashrightarrow \: 5x + 2x + 3x - 60\degree + 40\degree - 80\degree = 180 \degree[/tex]
[tex]\qquad \sf \dashrightarrow \: 10x - 100\degree = 180\degree[/tex]
[tex]\qquad \sf \dashrightarrow \: 10x = 180\degree + 100\degree[/tex]
[tex]\qquad \sf \dashrightarrow \: 10x = 280\degree[/tex]
[tex]\qquad \sf \dashrightarrow \: x = 280\degree \div 10[/tex]
[tex]\qquad \sf \dashrightarrow \: x = 28\degree[/tex]
The value of x is 28°
