The least number of mice that he has to take out of his hat would be 23.
We have the following details to solve this problem
x = 14
t = 8
u = 6
n1 = x + t + 1
= 14 + 8 + 1 = 23
n2 = t + u + 1
= 8 + 6 + 1 = 15
n3 = x + u + 1
= =14+6+1=21
From here the
max n (n1, n2, n3) = 23, 15, 21
Hence the least number that has to be taken out would be 23.
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