Respuesta :
Given the value for S2- as 3.42 x 10-17 M find the value of Ag+. (2:1 ratio). Ag2S W ... 4.00 x10 M ... First,calculate the number of moles in solution by multiplying volume and .... To find the number of grams of oxygen: 100 – (31.7 + 5.30) = 63.0.
The number of moles in 4.00 × 10² g of Cesium iodide is 1.55 mol.
How to find the number of moles ?
To calculate the number of moles of a substance, we have to divide the given mass/weight of the substance by the molar mass of the substance.
Number of moles = [tex]\frac{\text{Given Mass}}{\text{Molar mass}}}[/tex]
Now, calculate the molar mass of Cesium Iodide
Molecular formula of Cesium iodide is CsI
Molar mass of Cesium iodide (CsI)
= 132 + 126
= 258 g/mol
Now, put the values in above formula we get
Number of moles = [tex]\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
= [tex]\frac{4.00 \times 10^2 g}{258\, g/mol}[/tex]
= [tex]\frac{400}{258\, mol^{-1}}[/tex]
= 1.55 mol
Thus, from the above conclusion we can say that The number of moles in 4.00 × 10² g of Cesium iodide is 1.55 mol.
Learn more about the Moles here: https://brainly.com/question/13314627
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