Answer: D) [tex]33.3\mu\text{m}[/tex]
Explanation:
If we assume the shape of algae cell is round or sphere.
Given: The total number of algae cells spanning the field of view = 15
At 40x field of view is [tex]0.50\text{ mm or }500\mu\text{m}[/tex]
To calculate the diameter of one algae we need to divide [tex]500\mu\text{m}[/tex] by the total number algae calls spanning the field , we get
The diameter of one algae cell :
[tex]\dfrac{500\mu\text{m}}{15}=33.33333333\mu\text{m}\approx33.3\mu\text{m}[/tex]
Hence, the diameter of one algae cell [tex]\approx33.3\mu\text{m}[/tex]
Answer:
Option D
Explanation:
The field of view is 0.50 mm or 500um.
Thus, if this span of view has 15 algae cells then these algae cells are arranged in linear order adjacent to each other.
Hence the sum of diameter of all fifteen algaes is equal to 500um
Now , the actual size of view
[tex]= 500[/tex] um
sum of diameter of 15 algae [tex]= 500[/tex]um
Diameter of one algae cell is equal to [tex]\frac{500}{15} \\= 33.33[/tex]um
Hence, option D is correct
