Using function concepts, it is found that:
For a quadratic function in the following format:
[tex]f(x) = ax^2 + bx + c[/tex]
In this problem, the function is:
[tex]f(x) = x^2 - 2x + 3[/tex]
Hence the coefficients are: [tex]a = 1, b = -2, c = 3[/tex].
Then:
[tex]-\frac{b^2 - 4ac}{4a} = -\frac{(-2)^2 - 4(1)(3)}{4} = 2[/tex]
Hence, the range is [tex](2, \infty)[/tex].
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