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A circuit contains three resistors connected in parallel. the value of r1 is 100 , the value of r2 is 400 , and the value of r3 is 330 . if this circuit is supplied with 40 vdc, what is the circuit current?

Respuesta :

1/Re = 1/R1 + 1/R2 + 1/R3

1/Re = 1/100 + 1/400 + 1/330

1/Re = 0.01553

Re = 64.59

I = V/R

I = 40V / 64.59

= 0.6212 A

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