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earths oceans have an average depth of 3800 m, a total area of 3.63 *10^8 km^2, and an average concentration of dissolved gold of 5.8*10^-9 g/L. If a recent price of gold was $883.00 troy/oz, what is the value of gold in the ocean? (1 troy oz=31.1g)

Respuesta :

HomertheGenius
1 m² = 1000 L
Volume = 3800 m * 3.63 * 10 ^14 m² = 13,794 * 10 ^14 m³ =
= 13,794 * 10^17 L
Mass ( gold ) = 13,794 * 10 ^17 L * 5.8 * 10 ^(-9 ) g / L =
= 80,005.2 * 10 ^12 g : 31.1 = 2,572.5 * 10 ^12 troy oz
The value of gold in the ocean:
$883.00 * 2,572.5 * 10^12 = $2271517.5 * 10 ^12 ≈ $ 2.27 * 10^18

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