Hi there!
We can use the kinematic equation:
[tex]v_f^2 = v_i^2 + 2ad[/tex]
vf = Final velocity (? m/s)
vi = initial velocity (0 m/s, dropped from rest)
a = acceleration (due to gravity, 9.8 m/s²)
d = distance (9.8 m)
Simplify the equation to solve for vf:
[tex]v_f^2 = 0 + 2ad\\\\v_f = \sqrt{2ad}[/tex]
Substitute in the given values:
[tex]v_f = \sqrt{2(9.8)(9.8)} = \boxed{13.86 m/s}[/tex]
