If m ∥ n, m∠1 = (5x + 12)°, and m∠2 = (7x – 16)°, what is m∠3?

Answer:
98°
Step-by-step explanation:
m∠1 = m∠2
5x + 12 = 7x - 16; substitute the given
2x = 28
x = 14
m∠2 + m∠3 = 180; supplementary angles
82 + m∠3 = 180
m∠3 = 180 - 82
m∠3 = 98 degrees
Answer: m<3 = 98
Explanation: If two parallel lines are cut by a transversal,
then alternate interior angles are congruent.
This means that the m<1 = m<2.
So we can setup the equation 5x + 12 = 7x - 16
and solving this equation gives us x = 14.
Now let's use <2 to help us find the m<3.
Since x = 14, we can plug a 14 into the equation for x
to find the m<2 and this gives us 7(14) - 16 which is 82.
Now, we know that <2 and <3 form a straight
angle which is equal to 180 degrees.
So we can say that 82 + m<3 = 180 and we find that m<3 = 98.