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A player transfers a momentum of 12 kg m/s to a ball of mass 400 g which is at rest. Find the work done on the ball.

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Lanuel

The work done on the ball is equal to 180 Joules.

Given the following data:

  • Momentum = 12 kgm/s.
  • Mass of player = 400 g

Conversion:

1000 grams = 1 kg

400 grams = X kg

Cross-multiplying, we have:

[tex]X=\frac{400}{1000} =0.4 \;kg[/tex]

To calculate the work done on the ball:

First of all, we would determine the velocity of the ball.

The formula for momentum.

Mathematically, momentum is given by the formula;

[tex]Momentum = mass \times velocity\\\\12=0.4 \times velocity\\\\Velocity=\frac{12}{0.4}[/tex]

Velocity = 30 m/s.

Now, we can calculate the work done on the ball:

Note: The work done on the ball is equal to the change in kinetic energy possessed by the ball.

[tex]Work\;done = \Delta K.E\\\\Work\;done =\frac{1}{2} MV^2[/tex]

Substituting the parameters into the formula, we have;

[tex]Work\;done =\frac{1}{2} \times 0.4 \times 30^2\\\\Work\;done =0.2 \times 900[/tex]

Work done = 180 Joules.

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